construct a triangle pqr with base and QR =3.8 CM angle Q= 75°and PQ + PR =7.9 cm
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Answered by
10
Step-by-step explanation:
STEP I: Draw a line QR of length 7 cm and contruct angle XQR=75°
STEP II:Cut a line segment QM=3 cm(PQ-PR)
STEP III: Join M and R and draw the Perpendicular Bisector of MR and the point at which it cuts QX will be P.
STEPIV: join P and R and the triangle PQR is Constructed.
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4
Answer:
it is wrong answer
Step-by-step explanation:
because it's terms are didn't match with the question.
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