Question

construct a triangle pqr with base and QR is equal to 3.8 CM angle Q is equal to 75 degree and PQ + PR is equal 7.9 cm​

Answer 1

Answer:

.Draw base BC=7cm

2.Let's draw ∠B=75

∘

.Let the ray be BX

3.Open the compass to length AB+AC=13cm.From point B as center, cut an arc on ray BX.Let the arc intersect BX at D

4.Join $$CD$

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:△ABC is the required triangle.

solution

Step-by-step explanation:

Mark me as BRAINLIEST

Answer 2

Answer:

same

Step-by-step explanation:

$75d$

true axually