Construct a triangle PQR with its perimeter= 11cm and the base angles of 75degree and 30 degree.
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The below given steps will be followed to construct the required triangle.
Step I: Draw a line segment AB of 11 cm.
(As PQ + QR + PR = 11 cm)
Step II: Construct an angle, ∠XAB, of 75 at point A and an angle, ∠YBA, of 30 at point B.
Step III: Bisect ∠XAB and∠YAB. Let these bisectors intersect each other at point P
Step IV: Draw perpendicular bisector ST of PA and UV of PB
Step V: Let ST intersect AB at Qand UV intersect AB at R.
Join PQ and QR
ΔPQR is the required triangle.
Step I: Draw a line segment AB of 11 cm.
(As PQ + QR + PR = 11 cm)
Step II: Construct an angle, ∠XAB, of 75 at point A and an angle, ∠YBA, of 30 at point B.
Step III: Bisect ∠XAB and∠YAB. Let these bisectors intersect each other at point P
Step IV: Draw perpendicular bisector ST of PA and UV of PB
Step V: Let ST intersect AB at Qand UV intersect AB at R.
Join PQ and QR
ΔPQR is the required triangle.
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