Question

construct a triangle PQR with PQ =3 cm QR =5 cm and PQR =60°​

Answer 1

Answer:

Construct triangle PQR given that PQ=3cm, QR=5.5cm and angle PQR=60 degree.

draw a line segment qr measuring 5.5 cm.

construct 60 degrees at point q.

extend ray qx. With radius 3 cm cut an arc intersecting ray qx at point p.

join line segment pr to obtain triangle pqr.

Answer 2

Answer:

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Step-by-step explanation:

First, draw a base of 5 cm according to the rough figure drawn at the left corner and then mark an angle of 60° with the help of a protractor. You get an angle AQR. Draw and arc on AQ of 3 cm from point Q and name it as Point P. Now, join the points P, Q and R and here, you get the desired construction.