Question

construct a triangle pqr with PQ 4 cm, PR 4.6 cm and angle P 75​

Answer 1

Step-by-step explanation:

draw a line segment PQ 4cm.

take center as P draw 75 degree.

take center as P draw 4.5cm in 75 degree line and named it R.

and join RQ

Answer 2

ΔPQR is Constructed with PQ 4 cm, PR 4.6 cm and angle P 75​°

Step-by-step explanation:

Step 1 : Draw a line segment PQ  =  4 cm with the help of ruler

Step 2 : Draw an angle of 75° at P on PQ using protector

Step 3 : Take a length of 4.6 cm from P on the angle drawn in step 2 and label another end as PR

Step 4 : join QR

ΔPQR is Constructed

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