construct a triangle SBC such that AB 6cm BC 4.5 cm and AC is 5.5 cm. construct circumcircle of this triangle
Answers
Answer:
Steps of construction:
(i) Draw a line segment BC = 4.5 cm
(ii) With centre B and radius 6 cm, draw are
Arc
(iii) With centre C and radius 5.5 cm, draw
another are intersecting the first arc at A.
(iv) Join AB and AC.
∆ ABC is the required triangle.
(v) Draw the perpendicular bisectors of AB
and AC. Which intersect each other at O.
(vi) Join OB, OC and OA.
(vii) With centre O, and radius OA, draw a circle
which passes through A, B and C.
This is the required circum circle of ∆ ABC.
(ii) Steps of Construction :
(i) Draw a line segment PQ = 6.5 cm
(ii) At Q, draw a ray making an angle of 75°.
(iii) Through P, with a radius of 6.5 cm, draw
an arc which intersects the angle ray at R.
(iv) Join PR,
∆ PQR is the required triangle.
(v) Draw the perpendicular bisectors of sides
PQ and PR intersecting each other at o.
(vi) Join OP, OQ and OR.
(vii) With centre O and radius equal to OP or
OQ or OR draw a circle which passes through P,Q and R. This is the required
circum circle of ∆ PQR
(iii) Steps of Construction:
(i) Draw a line segment AB = 5.5 cm
(ii) With centres A and B and radius 5.5 cm,
draw two arcs intersecting each other at c.
(iii) Join AC and BC.
∆ ABC is the required triangle.
(iv) Draw perpendicular bisectors of sides AC
and BC which intersects each other at 0.
(v) Join OA, OB, and OC.
(vi) With center o and radius OA or OB or OC,
draw a circle that passes through A, B and C. This is the required circumcircle.