construct a triangle shadow similar to the given triangle ABC , with its sides equal to 5/3 of the corresponding sides of the triangle AB
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Answer:
Let ΔABC be a triangle having BC=6cm;∠B=50°;∠C=60°.
Steps of construction of triangle (3/4)th of △ABC:
(1). Draw a ray BX making an acute angle with BC on the opposite side of vertex A.
(2). Mark four points on BX as B
1
,B
2
,B
3
,B
4
such that BB
1
=B
1
B
2
=B
2
B
3
=B
3
B
4
.
(3). Join B
4
C and draw a line through B
3
parallel to B
4
C intersect BC at C
′
.
(4). Draw a line C
′
parallel to AC intersect AB at A
′
.
Thus, ΔA
′
BC
′
is required triangle.
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