Question

construct a triangle similar to a given equitateral triangle pqr with sides 5cm such that each of its sides is 6/7 of corresponding sides of∆pqr​

Answer 1

Step-by-step explanation:

Steps of construction:

1. Draw a line segment QR = 5 cm.

2. With Q as centre and radius = PQ = 5 cm, draw an arc.

3. With R as centre and radius = PR = 5 cm, draw another arc meeting the arc drawn in step 2 at the point P.

4. Join PQ and PR to obtain ΔPQR.

5. Below QR, construct an acute ∠RQX.

6. Along QX, mark off seven points Q1,Q2 , .........Q7 such that QQ1 = Q1Q2 = Q2Q3 = ............. = Q6Q7.

7. Join Q7R.

8. Draw Q6R' || Q7R.

9. From R' draw R'P' || RP.

Hence, P'QR' is the required triangle..

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Answer 2

Step-by-step explanation:

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