construct a triangle similar to a given triangle ABC with its side equal to 5/3 of the corresponding sides of the triangle ABC ( i . e ., of scale factor 5/3 ) .
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Step-by-step explanation:
Steps of construction
(1).Draw any ray PX making an acute angle with PQ on the side opposite to the verterx Q.
(2).Mark four points on PX P
1
,P
2
,P
3
and P
4
on PX so that PP
1
=P
1
P
2
=P
2
P
3
=P
3
P
4
(3).Join P
4
Q and draw a line through P
3
parallel to P
4
Q, to intersects PQ at Q
′
.
(4).Draw a line through Q
′
parallel to the line QR to intersect PR at R
′
.
Thus the required triangle.
Hence, this is the answer.
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