Question

Construct a triangle similar to a given triangle pqr with its sides equal to 3/5 of the corresponding sides of the triangle pqr (scale factor 3/5<1)​

Answer 1

Step-by-step explanation:

(1) Draw any ray QX making an acute angle with QR on the side opposite to the vertex P. (2) Locate 3 (the greater of 2 and 3 in 2/3) points.  Q1Q2, Q2 on QX so that QQ1 = Q1Q2 = Q2Q3 (3) Join Q3 R and draw a line through Q2 (the second point, 2 being smaller of 2 and 3 in 2/3) parallel to Q3 R to intersect QR at R’. (4) Draw line through R’ parallel to the line RP to intersect QP at P’. The ΔP’QR’ is the required triangle each of the whose sides is 2/3 of the corresponding sides of 3 ΔPQR.Read more on Sarthaks.com - https://www.sarthaks.com/944912/construct-triangle-similar-given-triangle-sides-equal-corresponding-sides-triangle-factor