construct a triangle similar to given triangle in which AB=4cm , BC = 6 cm and angle ABC =60 degree such that each side of the new triangle is 3by 4 of given triangle ABC.
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Hii There ...
Here is ur answer...
Steps of construction:-
1.Draw BC=6cm.
2.At point B draw angle YBD=60° and draw an arc BA=4cm.
3.Join AC thus∆ ABC is formed.
4.Draw a ray BX making an acute angle DBX with BD.
5.Join B3D
6.Draw B3D llB4C such that BB3/B3B4 =BD/DC.
{ BY BPT}.
7.Join DE which intersects BY at E.Such that DE ll AC
8. By Thale's Theorem we get BD/DC=BE/EA .
9.Thus ∆BED is formed which is 3/4th of ∆ABC.
HOPE IT HELPS☺️.
MARK AS BRAINLIEST PLZZ...
Here is ur answer...
Steps of construction:-
1.Draw BC=6cm.
2.At point B draw angle YBD=60° and draw an arc BA=4cm.
3.Join AC thus∆ ABC is formed.
4.Draw a ray BX making an acute angle DBX with BD.
5.Join B3D
6.Draw B3D llB4C such that BB3/B3B4 =BD/DC.
{ BY BPT}.
7.Join DE which intersects BY at E.Such that DE ll AC
8. By Thale's Theorem we get BD/DC=BE/EA .
9.Thus ∆BED is formed which is 3/4th of ∆ABC.
HOPE IT HELPS☺️.
MARK AS BRAINLIEST PLZZ...
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