construct a triangle the measure the angle are 32 degree 58 degree and 90 degree measure the length of sides of the triangle find sin 32 degree and Cos 32 degree find the value of sin^2 32 degree + cos^2 32 degree
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Sin32 = BC/AC = 0.53 & Sin²θ = BC²/AC² =0.28 and Cosθ = AB/AC =0.85 & Cos²θ = AB²/AC² =0.72
Step-by-step explanation:
right angled ∆ ABC
∠B = 90°
∠A = 32°
∠C = 58°
Draw a line segment AB
Draw an angle of 90 deg at B on AB using setsquare / protector
Draw an acute angle 32° at A on AB using protector such that it intersect angle drawn earlier at C
ΔABC is constructed
AB = Base
BC = Perpendicular
AC = hypotenuse
Sin32 = Perpendicular / Hypotenuse
=> Sin32 = BC/AC = 0.53
Sin²θ = BC²/AC² = 0.28
Cosθ = Base / Hypotenuse
=> Cosθ = AB/AC = 0.85
Cos²θ = AB²/AC² = 0.72
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