Question

construct a triangle whose perimeter is 11.9 and base angles are 80°and 60°​

Answer 1

Answer:

1. Draw a line segment PQ = AB + BC + CA = 12 cm.

2. Make ∠ LPQ= 45° and ∠ MQP = 60°

3. Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A.

4. Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively.

5. Join AB and AC.

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Step-by-step explanation:

Answer 2

Steps to be followed to construct a triangle with given conditions.

1) Draw a line segment PQ = AB + BC + CA = 11.9 cm

2) Make ∠ LPQ= 80° and ∠ MQP = 60°

3) Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A.

4) Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively.

5) Join AB and AC.

Done, you'll get you triangle after following these steps...!!