Construct a triangle whose perimeter is12cm and side ratio is 1:2:3
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IN ORDER TO CONSTRUCT THE TRIANGLE:-
First of all we have to find its sides.
Given :-
Ratio of sides = 1:2:3
Sides are 1x, 2x , 3x
Now, perimeter of triangle = sum of sides
12 = x + 2x + 3x
=> 6x = 12
=> x = 2
Therefore, the sides of the triangle are 2cm, 4cm and 6cm.
For Construcing Triangle ABC we have,
AB = 6cm
BC = 2cm
CA = 4cm
STEPS OF CONSTRUCTION :-
1.Draw line segment CA of 4cm.
2.Construct arc of 6cm from point A and arc of 2cm from point C by using compass.
3.The point of intersection of both the arcs is point B.
4.Join B to C and A. Now the triangle is constructed.
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Perimeter =12cm
Sum of ratio =1+2+3
=6
1/6*12=2cm
2/6*12=4cm
3/6*12=6cm
As you got the measures you can make triangle easily
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