construct a triangle whose permiter is 6.4 and the base angles are 60 and 45
Answers
Answer:
The steps of the required construction are:
1) Draw a line segment DE=6.4cm. Using a protractor, draw ∠EDF=60° and ∠DEG=45°. Join DF and EG. Taking D as the center and any radius, draw an arc, intersecting DE at H and DF at I. Similarly, Taking E as the center and any radius, draw an arc, intersecting DE at J and EG at K.
2) Taking H as the center draw an arc of any radius greater than . Now, Taking I as the center and the keeping the same radius, draw another arc, intersecting the previous arc at L. Join and extend DL. Similarly, Taking J as the center draw an arc of any radius greater than . Now, Taking K as the center and the keeping the same radius, draw another arc, intersecting the previous arc at M. Join and extend EM, intersecting extended DL at A.
3) Taking D as the center and radius greater than , draw arcs on each side of AD. Now, taking A as the center and same radius, draw arcs, intersecting the previous arcs at points N and O. Join and extend NO. Extended NO intersects line segment DE at point C. Join AC. Similarly, Taking E as the center and radius greater than , draw arcs on each side of AE. Now, taking A as the center and same radius, draw arcs, intersecting the previous arcs at points P and Q. Join and extend PQ. Extended NO intersects line segment DE at point B. Join AB.
4) ∆ABC is the required triangle.
