Question

construct a triangle whose side 4,5,7​

Answer 1

Step-by-step explanation:

DrawBC=4cm.

DrawBC=4cm.Cut arc of 5 cm from B and arc of 7 cm from C. Mark point of intersection as A.

DrawBC=4cm.Cut arc of 5 cm from B and arc of 7 cm from C. Mark point of intersection as A.Draw BD making an acute angle with BC. Mark 4 equal arcs on BD.

DrawBC=4cm.Cut arc of 5 cm from B and arc of 7 cm from C. Mark point of intersection as A.Draw BD making an acute angle with BC. Mark 4 equal arcs on BD.Join B4 to C, draw a line B3C′ parallel to B4C.

DrawBC=4cm.Cut arc of 5 cm from B and arc of 7 cm from C. Mark point of intersection as A.Draw BD making an acute angle with BC. Mark 4 equal arcs on BD.Join B4 to C, draw a line B3C′ parallel to B4C.Draw a line C′A′ parallel to CA.

Answer 2

DrawBC=4cm.

Cut arc of 5 cm from B and arc of 7 cm from C. Mark point of intersection as A.

Draw BD making an acute angle with BC. Mark 4 equal arcs on BD.

Join B4 to C, draw a line B3C′ parallel to B4C.

Draw a line C′A′ parallel to CA.

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