Math, asked by sharikasinha315, 1 month ago

Construct a triangle whose sides que 36 cm, 3cm and 4.8 cm and bisect the largest angle.​

Answers

Answered by thimmaraja0987
4

Answer:

Answer

Steps of construction :

Step 1 : Draw a line AB = 4.8cm .

Step 2 : Now , take radius of 3cm and center 'A' draw an arc. And take radius of 3.6cm and center 'B' draw an arc that intersect our previous arc at 'C'.

Step 3 : Join CA and CB we get required triangle ABC. 

Now , we measure all internal angles and we get ∠ ABC is smallest angle , 

So, we bisect ∠ ABC . 

Step 4: Take any radius (less than half of AB) and center 'B' draw an arc that intersect our line AB at P and line BC at Q.

Step 5 : With same radius and center 'P' and 'Q' draw arc which intersect at 'R'.

Step 6 : Join BR and extended BR that line intersects AC at 'D'. 

Now , we can easily measure each other angle with the help of protractor. 


sharikasinha315: Thanks.
thimmaraja0987: No problem
sharikasinha315: ok
Answered by Sneha0801
28

Answer:

hello

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myself Sneha

from India

7th standard

14 age

your intro??

borahae

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