Question

construct a triangle wiht perimeter 9 cm. the sides are in ratio 1:2:3.​

Answer 1

Step-by-step explanation:

let the side be x,

$1x + 2x + 3x = 9cm \\ 6x = 9 \\ x = \frac{9}{6} \\ x = \frac{3}{2} \: \: (1.5cm) \\ \\ 1x = 1 \times 1.5 = 1.5cm \\ 2x = 2 \times 1.5 = 3cm \\ 3x = 3 \times 1.5 = 4.5cm$

So, the sides of the triangle are 1.5cm,3cm and 4.5 cm respectively.

Construction:

1. Draw a line segment AB=3cm.

2. With 1.5cm as radius, draw an arc using compass.

3. With 4.5cm as radius, draw an arc which intersect the previous arc at C using compass.

4. Now join A to C and B to C.

∴The required triangle is obtained.