Question

Construct a triangle with 50°,60°and perimeter=11cm

Answer 1

let consider side of triangle be x
therefore perimeter of triangle =sum of all sides
11 =x+x+x
11=3x
x=11/3
therefore draw the straight line of 11cm and divide it into three parts .join the third part of 11cm.
it will be your required points .
then from first point of the straight line of 11cm draw the angle of 50° also from 2nd point draw the angle of 60°
join the lines of angels you have drawn
it is the required triangle..
thank you...