Math, asked by shiv1978, 2 days ago

Construct a triangle with perimeter 10cm and base angle 60 degree and 45 degree​

Answers

Answered by qureshnihal
1

Answer:

Steps of Construction :

Draw a line segment, say XY equal to BC + CA + AB = 10 cm.

Make angle LXY equal to 60o and angle MYX equal to 45o.

Bisect LXY and MYX. ...

Draw perpendicular bisector PQ of AX and RS of AY.

Let PQ intersect XY at B and RS intersect XY at C.

Join AB and AC.

ABC is the required triangle.

Answered by sarojdewal400
0

Expert Answer:

Steps of Construction :

Draw a line segment, say XY equal to BC + CA + AB = 10 cm.

Make angle LXY equal to 60o and angle MYX equal to 45o.

Bisect LXY and MYX. ...

Draw perpendicular bisector PQ of AX and RS of AY.

Let PQ intersect XY at B and RS intersect XY at C.

Join AB and AC.

ABC is the required triangle.

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