Question

construct a triangle with perimeter 10cm and base angles 60° and 45° with steps

Answer 1

Hope this helps you....

Answer 2

The construction of ∆ABC having perimeter 10cm is attached.

Given:

• A triangle with perimeter 10cm.
• Base angles 60° and 45° .

To find:

• Construction of ∆ABC with steps.

Solution:

Steps of construction:

1. Draw a line segment XY of 10 cm, let say it is XY.
2. Draw an angle of 45° at X and 60° at Y, with the help of compass/protector.
3. Draw angle bisectors of both angles, let these are $\angle PXY$ and $\angle QYX$.
4. These angle bisectors met at a point, mark that point as A.
5. Draw perpendicular bisectors of lines PX and QY.
6. These perpendicular bisectors meet line segment XY at two points, mark these points ad B and C respectively
7. Draw the lines AB,AC and BC.
8. Construction of ∆ABC is done.

Verification:

On measurement it is found that

BC= 4 cm

AB= 3.5 cm

AC= 2.5 cm

AB+BC+AC=10 cm

Base angles $\angle B= 45^{\circ}$ and $\angle C= 60^{\circ}$.

Hence verified.

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Learn more on construction:

1) Construct ΔXYZ, in which YZ=6 cm, XY+XZ=9 cm. ∠XYZ = 50°

https://brainly.in/question/11760132

2) construct a triangle ABC in which AC=6.2 cm

, ∠C=60° and AB-BC = 2.5 cm

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