Question

construct a triangle with sides 4cm 5cm 7cm then construct a triangle similar to it whose sides are 2/3 of the corresponding sides of the given​

Answer 1

Step-by-step explanation:

Now from B draw any ray BX making an acute ∠CBX with base BC on the side opposite to the vertex A. 5. Along BX Mark 3 points B1,B2,B3, on BX such that BB1 = B1B2 = B2B3 . ... Thus , ∆MBN is the required triangle whose sides are 2/3 of the corresponding sides of ∆ABC.

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Answer 2

Answer:

Now from B draw any ray BX making an acute ∠CBX with base BC on the side opposite to the vertex A. 5. Along BX Mark 3 points B1,B2,B3, on BX such that BB1 = B1B2 = B2B3 . ... Thus , ∆MBN is the required triangle whose sides are 2/3 of the corresponding sides of ∆ABC.