Question

construct a triangle with sides 5cm,6cm,7cm
& then another triangle whose side are 7/5 of the
corresponding sides of the first triangle,​

Answer 1

Let the ∆ be ABC

Let side AB be 5cm

Let side BC be 6cm

Let side AC be 7cm

Now to construct another ∆

Let the other ∆ be LMN

In which, seg LM:

7 = 5

5

5 x 5

7

= 3.5cm

seg MN:

7 = 6

5

5 x 6

7

= 4.2cm

seg LN:

7 = 7

5

5 x 7

7

= 5cm

Hence we got the segments of the another ∆