Question

Construct a triangle xyz in which angle y=30°, z=90°
and
xy + yz + zx = 11cm

grd 9 Ch-constructions

I have written the answer
but I want explanation because I forgot how to do it

if you are very good at math then only answer

because it's very hard​

Answer 1

See the Attachment

Step by step shown Above

Answer 2

Answer:

Question 4:

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.

ANSWER:

The below given steps will be followed to construct the required triangle.

Step I: Draw a line segment AB of 11 cm.

(As XY + YZ + ZX = 11 cm)

Step II: Construct an angle, ∠PAB, of 30° at point A and an angle, ∠QBA, of 90° at point B.

Step III: Bisect ∠PAB and ∠QBA. Let these bisectors intersect each other at point X.

Step IV: Draw perpendicular bisector ST of AX and UV of BX.

Step V: Let ST intersect AB at Y and UV intersect AB at Z.

Join XY, XZ.

ΔXYZ is the required triangle.

Explanation:

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