Question

construct a triangle xyz in which angle Y=40°,Z=80° xy+yz+zx=11cm​

Answer 1

Answer:

✡

build it like this as i have made and you can score good marks

Step-by-step explanation:

this is really easy because the upper triangle have 4 sides

Answer 2

Answer:

Step 1: A line segment AB= 11 cm is drawn. (XY + YZ + ZX = 11 cm)

Step 2: An angle, ∠A= 30° is constructed at point A and an angle ∠B = 90° at point B.

Step 3: ∠A and ∠B are bisected . The bisectors of these angles intersect each other at point X.

Step 4: Perpendicular bisectors TS of AX and ZU of BX are constructed.

Step V: Let TS intersect ABat Y and ZU intersect AB at Z. XY and XZ are joined.

Thus, ΔXYZ is the required triangle.