Question

Construct a triangle XYZ in which angle y=90' , XY = 4.5 cm
and xz-yz = 2.2cm​

Answer 1

Answer:Step-1: Draw the base line segment QR= 6 cm.  

Step-2 : From Q, draw an angle ofusing compass, say ∠XQR.

Step-3 :Extend the line QX in the opposite direction as well to T. Cut a line segment QS of 2 cm from the line segment QT  extended in the opposite side of line segment XQ. Now join the point to R in order to get SR.

Step-4 : Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.

Thus ΔPQR is the required triangle.

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Answer 2

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Answer:Step-1: Draw the base line segment QR= 6 cm.  

Step-2 : From Q, draw an angle ofusing compass, say ∠XQR.

Step-3 :Extend the line QX in the opposite direction as well to T. Cut a line segment QS of 2 cm from the line segment QT  extended in the opposite side of line segment XQ. Now join the point to R in order to get SR.

Step-4 : Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.

Thus ΔPQR is the required triangle.