Question

Construct a triangle XYZ in which Y = 30°, Z = 90° and XY + YZ + ZX = 11 cm. Write the steps

of construction.​

Answer 1

Answer

1.Draw a line segment BC = XY + YZ + ZX (= 11 cm).

1.Draw a line segment BC = XY + YZ + ZX (= 11 cm).2.Make ∠LBC = ∠Y (= 30°) and ∠MCB = ∠Z (= 90°).

1.Draw a line segment BC = XY + YZ + ZX (= 11 cm).2.Make ∠LBC = ∠Y (= 30°) and ∠MCB = ∠Z (= 90°).3.Bisect ∠LBC and ∠MCB. Let these bisectors meet at a point X.

1.Draw a line segment BC = XY + YZ + ZX (= 11 cm).2.Make ∠LBC = ∠Y (= 30°) and ∠MCB = ∠Z (= 90°).3.Bisect ∠LBC and ∠MCB. Let these bisectors meet at a point X.4.Draw perpendicular bisectors DE of XB and FG of XC.

1.Draw a line segment BC = XY + YZ + ZX (= 11 cm).2.Make ∠LBC = ∠Y (= 30°) and ∠MCB = ∠Z (= 90°).3.Bisect ∠LBC and ∠MCB. Let these bisectors meet at a point X.4.Draw perpendicular bisectors DE of XB and FG of XC.5.Let DE intersect BC at Y and FG intersect BC at Z.

1.Draw a line segment BC = XY + YZ + ZX (= 11 cm).2.Make ∠LBC = ∠Y (= 30°) and ∠MCB = ∠Z (= 90°).3.Bisect ∠LBC and ∠MCB. Let these bisectors meet at a point X.4.Draw perpendicular bisectors DE of XB and FG of XC.5.Let DE intersect BC at Y and FG intersect BC at Z.6.Join XY and XZ.

Answer 2

Step-by-step explanation:

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