Question

construct a triangle XYZ in which∆Y=30°,∆Z=90°,XY+YZ+ZX=11cm​

Answer 1

Answer:Steps of construction

1) Draw a line segment AB = XY + YZ + ZX = 11 cm.

2) Draw a 30° angle at point a with one arm AB (∠LAB = 30°).

3) Construct a right angle at point B with one arm BA (∠MBA = 90).

4) Bisect ∠LAB and ∠MBA. Let these bisectors meet at point X.

5) Construct a perpendicular bisector of XA and XB and let their bisectors intersect AB at Y and Z respectively.

6) Join XY and XZ.

ΔXYZ is the required triangle