Question

Construct a triangle XYZ in which _Y = 30°, ZZ = 90° and XY+YX + ZX
= 11cm. Write steps of construction also.​

Answer 1

Answer:

your questions is wrong brother

Answer 2

Answer:

Draw a line segment BC = XY + YZ + ZX (= 11 cm).

Make ∠LBC = ∠Y (= 30°) and ∠MCB = ∠Z (= 90°).

Bisect ∠LBC and ∠MCB. Let these bisectors meet at a point X.

Draw perpendicular bisectors DE of XB and FG of XC.

Let DE intersect BC at Y and FG intersect BC at Z.

Join XY and XZ.