Construct a ΔXYZ in which ∠Y = 45°, ∠Z = 75° and XY + YZ + ZX = 12 cm.
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Step-by-step explanation: Draw a line BC = 12cm(xy+yz+zx=12cm) Draw ∠LBC = ∠Y = 45° and ∠MCB = ∠Z = 90° Bisect ∠LBC and ∠MCB meeting at point x. Now, construct the perpendicular bisectors of FG of XC and DE of XB.
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Step-by-step explanation:
(i) Draw a line segment which is sufficiently long using ruler.
(ii) Locate points X and Y on it such that XY=5cm.
(iii) At Y, construct a line segment YW, sufficiently large, such that ∠XYZ=100˚ ; use protractor to measure 100˚
(iv) With Y as centre and radius 5.5 cm, draw the line cutting YW at Z; join XZ.
⇒ Then XYZ is the required triangle.
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