Construct a ∆XYZ in which YZ=4.2 cm angle Y=120 degree and XY=3.9 cm. Draw XP perpendicular ZY( produced if required)
Answers
Answered by
41
hope this helps You!!!!
Attachments:
Answered by
4
Answer:
This is the required ΔXYZ and XP⊥YZ
Step-by-step explanation:
As per the data given in the question
we have to construct ΔXYZ and draw XP⊥YZ
As per the questions
It is given that
YZ=4.2 cm angle Y=120 degree and XY=3.9 cm
- First draw the line segment YZ=4.2 by using ruller.
- At point Y draw an arc which is cut the line segment at point M by using compass.
- Again at point M draw 3 arcs which is cut the previous arc at point A and B.
- join the point BY and extend it.
- At point Y measure 3.9 cm and cut the line BY at point X.
- Now join the point XZ and we will get ∡xyz = 120° then foot of perpendicular from X to YZ lies externally. Extend ZY
- Take a arc on extended ZY cut at S and T
- Draw perpendicular bisector of ST which also pass through X and cut YZ at Point P.
- Now XP⊥YZ
- This is the required ΔXYZ and XP⊥YZ
For such type of question:
https://brainly.in/question/33876235
#SPJ1
Similar questions