Construct _ABC =60° and bisect it.
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*STEPS OF CONSTRUCTION*
Draw, ∠ABC = 60°
Draw BD, the bisector of ∠ABC.
Taking B as centre, draw an arc of radius 2.5 cm.
Taking C as centre, draw another arc of radius 2.5 cm.
Draw a line MN which touches these two arcs drawn. Then MN is the required line parallel to BC.
Let this line MN meets AB at P and bisector BD at Q.
Measure BP and PQ.
By measurement we see BP = PQ
Step-by-step explanation:
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