Math, asked by bhavana9620654038, 11 months ago

construct ∆ABC given BC=5cm,angle B=45° and AC=AB=2.5cm.

Answers

Answered by prince3641
2

Step-by-step explanation:

...draw base bc as 5cm draw angle b as 45degree by constructing biswctor of 90degree

......by taking b as center draw an arc on the ray of raddi 2.5cm.name the point a

.....join ac

Answered by pariiiisharma02
0

Answer:

triangle ABC is a equilateral triangle....steps to make are given below...

Step-by-step explanation:

make a line segment of 5 cm and name it...BC.

as, AC = AB we know the angles opposite to these sides will be equal i.e. B=C

now make angles of 45 degrees from point B and C.

extend both lines.

the point where they intercept...mark is A

OR

mark arcs of 2.5 cm from point B and point C. the point where they intercept is point A.

FINALLY, JOIN A TO B THEN A TO C.

THEREFORE THE TRIANGLE IS CONSTRUCTED.

HOPE THIS HELPED U !!!!

Similar questions