Question

Construct ∆ ABC in which AB=4 cm, BC=7 cm and cm and CA=3 cm. Which type of triangle is this?

Answer 1

Hey friend, Here is your answer-
By using Pythagores theorem ,
AB2+AC2 =BC2
(4)2+(3)2=(7)2
16+9=49
25 is not equal to 49.
Therefore the triangle is not right angled or equilateral triangle.
It is a scelene triangle.
Hope it will help you friend.

Answer 2

This is not a triangle, because there is a property of triangle according to which the sum of two sides of a triangle should be greater than the third side.
7+3=10 (10>4)
4+3=7 (7=7 not greater than it..)
Hence, this can't be a triangle.