Construct ∆ABC in which AB=5.8cm,BC+CA=8.4cm and angle B =60°
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Constructing triangle ABC in which AB = 5.8 cm , BC + CA = 8.4 cm and ∠B = 45°.
Step 1: Draw a line segment AB 5.8 cm.
Step 2 : Draw ∠B = 45°.
Step 3 : With Center B and radius 8.4 cm, make an arc which intersects BX at D.
Step 4 : Join D to A.
Step 5 : Draw a perpendicular bisector of segment DA it intersect the line segment BD at point C.
Step 6 : Join C to A.
ABC is the required triangle.
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