construct ∆ABC in which angle B=60°,AB=5cm and BC=6 cm
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hey mate
here your answer
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Explanation:
1. Draw AB =5 cm.
2. Using protractor draw B= 60°.
3. With C as center using compass and 6cm as radius cut an arc on the line drawn before to make B = 60°.
4.Name the intersection point as C.
5. Join B and C.we get the required triangle
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