Construct ΔABC in which BC = 10cm, ʟB = 600 and ʟC = 300
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Answer:
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Step-by-step explanation:
Construction:
A]. Draw the base BC and at the point, B makes an angle, say XBC equal to the given angle.
B]. Cut a line segment BD equal to AB+AC from the ray BX.
C]. Join DC and make an angle DCY equal to BDC.
D]. Let CY intersect BX at A
E]. ABC is the required triangle.
F]. In triangle ΔACD, ∠ACD=∠ADC.
G]. So, AB=BD–AD=BD–AC
H]. AB+AC=BD
From this we get, BD=14cm.
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Answer:
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Step-by-step explanation:
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