Question

Construct ∆ABC,in which BC=3.2, angle ACB=45°and perimeter of ∆ABC​

Answer 1

Answer:

Step 1: Draw a line segment BC 3.2 cm. Step 2 : Draw ∠C = 45° using protractor and draw a ray CX. Step 3 : With Center C and radius 10-3.2= 6.8 cm, make an arc which intersects CX at D. Step 5 : Draw a perpendicular bisector of segment DB it intersect the ray CX at point A