Construct ∆ ABC, in which BC =3.2cm, | ABC=45° and perimeter of ∆ ABC is10cm
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STEPS OF CONSTRUCTION
- Draw the line BC of 3.2cm
- Draw angle B of 45°
- With the centre B draw an arc of 10 cm (BD)
- Now join point C to point D
- Draw a bisector of line CD
- The point at which the bisector of line CD will intersect the line BD will be the point A
- Join the points
- ∆ ABC is the desired ∆
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