Question

construct ∆ ABC in which
BC=4.5cm ,AB=5.3cm and AC=5cm​

Answer 1

Step-by-step explanation:

•Draw a line AC=5cm

•Then draw an arc of 5cm from point A and an arc of 4.5cm from point C

•The arcs meet each other at a point. ....name the point as B

•Then take little more than half in the line BC and cut an arc in up and down from point B and C

•Draw a line from the contact of two arcs of up and two arcs of down

•This is the required triangle.