Question

construct ∆ABC in which BC = 5.5 cm, AB = 4.5 cm and AC=6cm. Through the vertex A of ∆ABC draw a line XY parallel to side BC. pls tell answer exams are going on​

Answer 1

.Steps of Construction:

(i) Draw BC = 4.6 cm.

(ii) With B as centre and radius equal to 5 cm draw an arc and with C as

centre and radius equal to 5.8 cm draw another arc to cut the previous arc at A.

(iii) Join AB and AC.

(iv) Make an acute angle ∠CBE.

(v) Set off three equal distances along BE at B1, B2 and B3.

(vi) Join B3C.

(vii) From B2 draw B2C' || B3C,meeting BC at C'.

(viii) Join AC'.

Then,ABC' is the required triangle.