Question

Construct ΔABC, in which BC=6.2 cm, ∠ACB=50°, AB+AC=9.8 cm

Answer 1

Answer:

Step-by-step explanation:

We have to construct the ΔABC in which BC = 6.2 Cm

And

AB + AC = 9.8 Cm

Angle C = 50°

We know that

Perimeter of triangle = sum of all sides = AB + BC + AC = 9.8 + 6.2 = 16 cm

So

We make a triangle with such measurements by first making

the line BC = 6.2 cm

And Angle C = 50

Then we make the AC of length = 4.95 cm and AB of length = 4.85 cm

And

Note that

4.95 + 4.85 + 6.2 = 16

That is

AB + AC = 9.8 cm

Which is the required condition

See the graph of triangle ΔABC in the figure below.

Answer 2

Construct ΔABC, in which BC=6.2 cm, ∠ACB=50°, AB+AC=9.8 cm