Question

construct ∆ABC in which BC= 6.2cm /B 70° and AB+AC=9cm​

Answer 1

Answer:

triangle ab is the required triangle

Step-by-step explanation:

As shown in the rough figure draw seg CB = 6.2 cm  Draw a ray CT making an angle of 50° with CB  Take a point D on ray CT, such that CD = 9.8 cm  Now, CA + AD = CD [C - A - D]  ∴ CA + AD = 9.8 cm …….(i)  Also, AB + AC = 9.8 cm ……(ii) [Given]  ∴ CA + AD = AB + AC [From (i) and (ii)] ∴ AD = AB  ∴ Point A is on the perpendicular bisector of seg DB  ∴ The point of intersection of ray CT and perpendicular bisector of seg DB is point A. Steps of construction:  i. Draw seg BC of length 6.2 cm.  ii. Draw ray CT, such that ∠BCT = 50°. iii. Mark point D on ray CT such that l(CD) = 9.8 cm.  iv. Join points D and B.  v. Draw perpendicular bisector of seg DB intersecting ray CT. Name the point as A.  vi. Join the points A and B. Hence, ∆ABC is the required triangleRead more on Sarthaks.com - https://www.sarthaks.com/849744/construct-abc-in-which-bc-6-2-cm-acb-50-ab-ac-9-8-cm?show=849746#a849746

Answer 2

Kindly refer this attachment...

I have written the steps below for better understanding.

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