Question

construct ∆ ABC in which BC=7cm angle b =40° and ∆ AC - AB = 3cm​

Answer 1

ABC =BC =7 CM

AC- AB =3CM

B =7 CM

Abc = 50cm

Answer 2

Construct ∆ ABC

We have to construct a triangle ABC with dimensions as:

BC=7 cm

∠B =40°

∆ AC - AB = 3 cm​

We will follow the below-mentioned steps to construct the ∆ ABC:

1. Draw base BC of length 7 cm

2. Now, we'll draw ∠B=40°. Let the ray be BX

3. Open the compass to length AC − AB = 3 cm  

From point B as center, cut an arc on ray BX. Let the arc intersect BX at D  

4. Join CD  

5. Now, we will draw perpendicular bisector of CD  

6. Mark point A where perpendicular bisector intersects BD  

7. Join AC

Hence, the ∆ ABC is formed as below: