Math, asked by shailamore74, 6 months ago


Construct ∆ABC, in which ZB = 70°, ZC = 60°, AB + BC + AC = 11.2cm​

Answers

Answered by biswasshubhmoy
3

Step-by-step explanation:

Given,

angle B=70°, angel C= 60° and AB+BC+AC=11.2cm

Let's construct a triangle ABC

Steps of construction

1. draw a line segment XY equal to AB+BC+AC=11.2cm

2. Make an angle equal to angle B = 70° form point X

Let the angle be LXY

3. Make an angle equal to angle C= 60° from point Y

Let the angle be MYX

4. Bisect angle LXY and MYX

let these angles bisect at point A

5. Make perpendicular bisector of AX

let it intersect XY at point B

6. Make a perpendicular bisector of AY

Let it intersect XY at point C

7. Join AB and AC

Hence, required triangle ABC is the required triangle

Answered by sujalhegde2006
0

Given,

angle B=70°, angel C= 60° and AB+BC+AC=11.2cm

Let's construct a triangle ABC

Steps of construction

1. draw a line segment XY equal to AB+BC+AC=11.2cm

2. Make an angle equal to angle B = 70° form point X

Let the angle be LXY

3. Make an angle equal to angle C= 60° from point Y

Let the angle be MYX

4. Bisect angle LXY and MYX

let these angles bisect at point A

5. Make perpendicular bisector of AX

let it intersect XY at point B

6. Make a perpendicular bisector of AY

Let it intersect XY at point C

7. Join AB and AC

Hence, required triangle ABC is the required triangle

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