Construct ∆ABC, in which ZB = 70°, ZC = 60°, AB + BC + AC = 11.2cm
Answers
Step-by-step explanation:
Given,
angle B=70°, angel C= 60° and AB+BC+AC=11.2cm
Let's construct a triangle ABC
Steps of construction
1. draw a line segment XY equal to AB+BC+AC=11.2cm
2. Make an angle equal to angle B = 70° form point X
Let the angle be LXY
3. Make an angle equal to angle C= 60° from point Y
Let the angle be MYX
4. Bisect angle LXY and MYX
let these angles bisect at point A
5. Make perpendicular bisector of AX
let it intersect XY at point B
6. Make a perpendicular bisector of AY
Let it intersect XY at point C
7. Join AB and AC
Hence, required triangle ABC is the required triangle
Given,
angle B=70°, angel C= 60° and AB+BC+AC=11.2cm
Let's construct a triangle ABC
Steps of construction
1. draw a line segment XY equal to AB+BC+AC=11.2cm
2. Make an angle equal to angle B = 70° form point X
Let the angle be LXY
3. Make an angle equal to angle C= 60° from point Y
Let the angle be MYX
4. Bisect angle LXY and MYX
let these angles bisect at point A
5. Make perpendicular bisector of AX
let it intersect XY at point B
6. Make a perpendicular bisector of AY
Let it intersect XY at point C
7. Join AB and AC
Hence, required triangle ABC is the required triangle