Question

. Construct ΔABC such that AB=3cm, BC=5cm and

AC=6cm. Measure ∠B.​

Answer 1

Answer:

I can't make it right now but I can give steps of construction...

Step-by-step explanation:

1. draw a line AC 6cm
2. from centreA as a point draw an are of 3cm
3. form the centre C draw an are 5cm that intercect previously drawn arc and mark the point as B
4. join AB and BC
5. Measure <B from protector.

And then we are done

Thank you your

brainly mate