Construct ∆ ABC such that , AB = 4.2cm, BC= 5.4 cm , AC = 6cm .
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Answer:
Construct AB =4.2 cm with scale on paper then from point A make an arc at a distance of 6cm above center of AB
now make an arc of 5.4cm from B also above the center of AB, Wherever these two arcs intersect it will be point C of your traingle
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Answer:
given below are the steps of construction.
Given:
- AB = 4.2cm
- BC= 5.4 cm
- AC = 6cm
To find:
the steps of construction.
Solution:
- start by constructing a line segment AB of length 4.2 cm.
- now, place your compass on vertice A and using your pencil, draw an arc of 6 cm.
- then, place your compass on vertice B and use your pencil to draw an arc of 5.4 cm. this arc should intersect the other arc. the point of intersection of these arcs is your point C.
- Join C to A (AC= 6) and C to B ( BC= 5.4 cm).
your triangle ABC has been constructed.
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