Construct △ ABC such that BC = 4 cm, AC = 5 cm and ABC = 90⁰
Answers
Step-by-step explanation:
hopes it's helps u the above pic
: Construct △ABC with m∠ABC=90
o
, BC=4cm and AC=5cm
To Construct: Construct △BXY similar to △ABC where the scale factor is
3
4
Steps of Construction:
(i) Construct △ABC with m∠ABC=90
o
,BC=4cm and AC=5cm.
(ii) In the half plane of
BC
not containing A, draw
BN
such that ∠CBN is an acute angle.
(iii) With some appropriate radius and centre B, draw an arc to intersect
BN
at B
1
. With the same radius and centre B
1
, draw and arc to intersect BN at B
2
such that B−B
1
−B
2
.
Similarly, with the same radius and centre B
k
, draw an arc to intersect BN at B
k+1
such that B
k−1
−B−B
k+1
, where k=2,3,....
(iv) Draw B
3
C
(v) Through B
4
, draw a ray parallel to B
3
C to intersect BC at X.
(vi) Through X, draw a ray parallel to CA to intersect BA at Y.
Thus △BXY is the required triangle