Math, asked by arnav13241, 5 months ago

Construct △ ABC such that BC = 4 cm, AC = 5 cm and  ABC = 90⁰​

Answers

Answered by pazhaniakshaiadhi
4

Step-by-step explanation:

hopes it's helps u the above pic

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Answered by srinandu2004
0

: Construct △ABC with m∠ABC=90

o

, BC=4cm and AC=5cm

To Construct: Construct △BXY similar to △ABC where the scale factor is

3

4

Steps of Construction:

(i) Construct △ABC with m∠ABC=90

o

,BC=4cm and AC=5cm.

(ii) In the half plane of

BC

not containing A, draw

BN

such that ∠CBN is an acute angle.

(iii) With some appropriate radius and centre B, draw an arc to intersect

BN

at B

1

. With the same radius and centre B

1

, draw and arc to intersect BN at B

2

such that B−B

1

−B

2

.

Similarly, with the same radius and centre B

k

, draw an arc to intersect BN at B

k+1

such that B

k−1

−B−B

k+1

, where k=2,3,....

(iv) Draw B

3

C

(v) Through B

4

, draw a ray parallel to B

3

C to intersect BC at X.

(vi) Through X, draw a ray parallel to CA to intersect BA at Y.

Thus △BXY is the required triangle

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