Question

construct ∆ABC such that BC = 6cm angleABC =80°
and
AC-AB = 2.5cm,​

Answer 1

Answer:

Steps of construction:

(1) Draw seg BC of length 6cm.

(2) Draw ray BE such that ∠CBE=100

∘

(3) Take point D on the opposite of ray BE such that BD=2.5cm.

(4) Construct the perpendicular bisector of seg DC.

(5) Name the point of intersection of ray BE and the perpendicular bisector of DC as A.

(6) Draw seg AC.

Therefore, ΔABC is required triangle.

Answer 2

Answer:

bro koi accha sa samjha saktha hai kya