Construct ∆ABC such that m LA = 55 ; m LB=60; and
I(AB)= 5.9cm
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Step-by-step explanation:
Steps to construct the triangle
Draw a line segment BC=6 cm
At B, draw ∠CBE=60
o
Draw BF⊥BE
Draw the perpendicular bisector of BC intersecting BF at O.
With O as centre and radius equal to OB or OC draw a circle.
With D as centre and radius 5 cm, mark a point A on the circle.
Join AB and AC. This gives △ABC
With B as centre and radius 8 cm, mark an arc which intersect BC produced in C'.
Draw a line parallel to AC at C'.
Extend the line segment BA, which intersect the line passing through C' in A'.
Thus, △A
′
BC
′
is the required triangle.
Here, △A
′
BC
′
∼△ABC
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